大家幫忙看看這道題答案

x9858627899

<interface>
2 q: c! K; l5 F+ ?; F  <loopback>
     <name>100</name>
( O* F4 A6 ~! d& T3 w) `     <enable>true</enable>
! Q( N/ V7 z! Y/ `1 T# J  </loopback>
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: ]9 I! g  R5 W0 x  ~1 `<interface>

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$ T3 g. v) s$ l, l
What is achieved by this code?
A. It displays the loopback interface
/ E; i5 w/ h2 z2 i6 j" `  uB. It renames the loopback interface
- V5 C! p. V! z  D( YC. It deletes the loopback interface
D. It unshuts the loopback interface


- P. ~1 V, Q# I9 |查不到啊...有些說D有些說A..沒有程式背景
- ]5 E+ M8 ~8 h7 n' l請各位幫忙看看唄
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lincc

D:
6 b, @- ~5 a% j6 a6 X5 h4 E, ]6 kenable就是noshut

thamky

D. It unshuts the loopback interface. Enable=true means unshut the port.

朱大帅爱皇马

D:
enable就是noshut:

jycert1

it should be D: enable the loopback 100

shangd

这不编程么？

tiang

D enable就是noshut