大家幫忙看看這道題答案

x9858627899

<interface>
- P2 M" P* {* h; H" ?, p1 L$ z& v  <loopback>
     <name>100</name>
3 U0 D) c: x' M/ ?3 u1 o- R9 a1 S6 W+ J     <enable>true</enable>
3 S8 [2 H9 W8 A  </loopback>
. J  s: R4 C' _$ V

0 u2 w) T% j/ d0 O/ b4 q1 m7 l4 Y" i<interface>

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% y. Q& u5 q9 K
0 ^5 X* |9 {  d/ R  ]/ i  d1 F# ]/ sWhat is achieved by this code?
A. It displays the loopback interface
  v4 Y; q0 F9 y, g0 w5 {' dB. It renames the loopback interface
* {6 c! J1 Z, R- fC. It deletes the loopback interface
D. It unshuts the loopback interface

8 m. Y( S% i3 M- ]
% C1 Q0 S! E6 L& Y查不到啊...有些說D有些說A..沒有程式背景
+ R  b, V( c+ _8 O- O0 ~請各位幫忙看看唄
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lincc

D:
enable就是noshut

thamky

D. It unshuts the loopback interface. Enable=true means unshut the port.

朱大帅爱皇马

3 q3 }4 K/ _' CD:
, n+ h& u+ n3 d$ @9 @enable就是noshut:

jycert1

it should be D: enable the loopback 100

shangd

这不编程么？

tiang

D enable就是noshut