14/02 马来西亚 300-101 878 Pass

jkpang

300-101 总共考了53题.

2 r9 a$ K  \1 b' q- S( q* o选择题 - 蛮多新题目。只记得这几题。
1. cef 的 forwarding information 收藏在哪
a. fib only
b. rib, fib, & adjacency table
$ U  A1 w, N4 }1 lc. fib & adjacency table
: _2 f/ h! ~3 F/ yd. adjacency table only
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2. log console 7
, h+ h8 o# ~0 P2 l4 C9 l6 x6 Qwhat is the effect of applying this command only without other logging command.
a. 忘了
b. 忘了
c. log will show on active console connection only
$ P, Q1 l/ D1 k$ }3 I) pd. 忘了
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; p0 Q- f4 x' m0 [& K1 Z& t4 |3. ntp stratrum (choose two correct)
stratrum 2 - 忘了
stratrum 1- directly connect to authoritative server
* h* H+ k& Z' K. c* A; f4 Ohighest stratrum level a valid ntp can have is 16
2 ]/ o! s3 _6 d+ \6 Z9 ^5 Mstratrum 0 - directly connect to authoritative server
stratrum 15 - invalid ntp
: U: r0 X& v; \+ _stratrum 2 - 忘了
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托图题 -
7 s4 b( Q7 F: m5 D# J1. frame relay
+ X4 a6 x$ l0 u9 Ttopology shown is a frame relay point-to-multipoint network. running config is attached but few config line hide.
% q& W2 _! H  R% yint s0
int s0.1 multipoint
+ y) i) }3 f+ S) W7 g4 Cencapsulation ppp
4 z0 S3 D6 |+ bencapsulation frame relay
frame-relay interface dlci xx (不是很记得）
3 v' n  r8 z' f- Pframe-relay map ip x.x.x.x broadcast （不是很记得）
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2. acl type (extended, dynamic, standard, time based, reflexive) 跟题库有点不一样
acl num 1300 - 1999
acl based on time
acl must use name
acl that use telnet for authentication
% [# u. J6 f' E' D9 {acl that place closest to source
2 [) X* r% i  a& F- j7 ^0 c
3. frame relay (svc, lmi, dlci, fecn, pvc) 跟题库一样的
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4. aaa
if-authenticated
local
none
: R0 J* M; I( M* J! z" d$ V- Egroup （不是很记得）
- F5 x, Z4 O/ T+ }tascas+ （不是很记得）
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实验题 - 跟题库一样的
( u2 ^2 ^% k! x$ w9 b6 q; C; r+ m! C1，2，4

. ^- ^, C1 `0 m4 i  ^; r' q- jNP 终于收官啦！！！
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jkpang

stratrum 15 - invalid ntp

Rockyw

恭喜，恭喜！

sidhoum

Congrats

ctfreedom

ctfreedom

jox

Congratulations, thank you

sidhoum

sidhoum

jox

Thanks for infos

jox

Thanks for infos

sidhoum

tyu564213

恭喜樓主
( D  k+ R+ f- e8 X
" m; e1 n; ^& d4 k想請教實驗題第4題  的  R4

# r$ n1 X% j/ A! e您最後的狀況是敲下  "ip summary-address eigrp 123 10.2.0.0 255.255.0.0"這行命令解決，

- f5 P+ l; k" k7 I. t9 ?還是  "ip summary-address eigrp 123 10.0.0.0 255.0.0.0"??

erezhazan1

thanks for the info !

愚愚愚

恭喜！！！！！