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助理工程师
 
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实验题4 最后有如下一句话:$ K0 n; A! S; k8 Q+ f
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6 q/ O, u: J& o M9 @2 \But please notice that the ip addresses and the subnet masks in your real
, S: I! O0 U' u( eexam might be different so you might use different ones to solve this question)
4 E2 N2 M+ g: ^* Q' TBut in your real exam, if you see the line “10.0.0.0/8 is a summary,….Null0″
: P( P' J4 {. Vthen you need to summary using the network 10.0.0.0/8 with the command “ip
+ i9 \; n/ z+ [& |- |( _) H. dsummary-address eigrp 123 10.0.0.0 255.0.0.0″ . This configuration is less
& P4 P& u; J; l5 Z1 j P4 woptimize than the first but it summaries into 2 subnets as the question requires。0 o9 s P* g" v8 E V, c& v* `9 M( E
7 n p( O J/ s8 h如果R3出现如下3条10.0.0.0的子路路由怎么办?如何修改呢?谢谢!
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' d8 {/ t i7 j$ y5 y& l 172.16.0.0/16 is variably subnetted, 2 subnets, 2 masks- R3 B) x h Z! j* J
D 172.16.0.0/16 is a summary, 02:10:13, Null0: Q2 S3 v8 i/ C; c* ]
C 172.16.1.0/24 is directly connected, Loopback1
3 q% d$ \! Z( R! M, G6 y 10.0.0.0/8 is variably subnetted, 3 subnets, 3 masks
& M; R0 D# p& E: Q8 B, u$ ZD 10.2.0.0/20 [90/2172416] via 10.2.3.4, 00:00:04, Serial0/04 j+ S# H2 S: j; E- K
D 10.0.0.0/8 is a summary, 00:05:49, Null0
" o3 Z( N9 ?8 m$ |1 K/ V2 MC 10.2.3.0/24 is directly connected, Serial0/0$ m1 m+ E3 j" _; _( V
r3#
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