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助理工程师
 
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3鸿鹄币
R1、2、3、6中使用EIGPRR2、3、4 中使用OSPF
只在R2上使用双向重分发
为什么R4 PING R6时走的是4-3-1-6,而R6 PING R4时走的是6-1-2-3-4
R3#show ip route
1.0.0.0/32 is subnetted, 1 subnets
D 1.1.1.1 [90/409600] via 10.1.13.1, 00:45:08, Ethernet0/1
2.0.0.0/32 is subnetted, 1 subnets
O 2.2.2.2 [110/11] via 10.1.23.2, 00:44:15, Ethernet0/0
3.0.0.0/32 is subnetted, 1 subnets
C 3.3.3.3 is directly connected, Loopback0
4.0.0.0/32 is subnetted, 1 subnets
O 4.4.4.4 [110/11] via 10.1.34.4, 00:44:15, Ethernet0/2
6.0.0.0/32 is subnetted, 1 subnets
D 6.6.6.6 [90/435200] via 10.1.13.1, 00:40:24, Ethernet0/1
10.0.0.0/24 is subnetted, 5 subnets
C 10.1.13.0 is directly connected, Ethernet0/1
D 10.1.12.0 [90/307200] via 10.1.13.1, 00:45:09, Ethernet0/1
D 10.1.16.0 [90/307200] via 10.1.13.1, 00:40:28, Ethernet0/1
C 10.1.23.0 is directly connected, Ethernet0/0
C 10.1.34.0 is directly connected, Ethernet0/2
R2#show ip route
1.0.0.0/32 is subnetted, 1 subnets
D 1.1.1.1 [90/409600] via 10.1.12.1, 00:12:17, Ethernet0/0
2.0.0.0/32 is subnetted, 1 subnets
C 2.2.2.2 is directly connected, Loopback0
3.0.0.0/32 is subnetted, 1 subnets
O 3.3.3.3 [110/11] via 10.1.23.3, 00:11:24, Ethernet0/1
4.0.0.0/32 is subnetted, 1 subnets
O 4.4.4.4 [110/21] via 10.1.23.3, 00:11:24, Ethernet0/1
6.0.0.0/32 is subnetted, 1 subnets
D 6.6.6.6 [90/435200] via 10.1.12.1, 00:07:33, Ethernet0/0
10.0.0.0/24 is subnetted, 5 subnets
D 10.1.13.0 [90/307200] via 10.1.12.1, 00:12:19, Ethernet0/0
C 10.1.12.0 is directly connected, Ethernet0/0
D 10.1.16.0 [90/307200] via 10.1.12.1, 00:07:37, Ethernet0/0
C 10.1.23.0 is directly connected, Ethernet0/1
O 10.1.34.0 [110/20] via 10.1.23.3, 00:11:26, Ethernet0/1
R4#show ip route
1.0.0.0/32 is subnetted, 1 subnets
O E2 1.1.1.1 [110/20] via 10.1.34.3, 00:47:45, Ethernet0/0
2.0.0.0/32 is subnetted, 1 subnets
O 2.2.2.2 [110/21] via 10.1.34.3, 00:47:45, Ethernet0/0
3.0.0.0/32 is subnetted, 1 subnets
O 3.3.3.3 [110/11] via 10.1.34.3, 00:47:45, Ethernet0/0
4.0.0.0/32 is subnetted, 1 subnets
C 4.4.4.4 is directly connected, Loopback0
6.0.0.0/32 is subnetted, 1 subnets
O E2 6.6.6.6 [110/20] via 10.1.34.3, 00:43:48, Ethernet0/0
10.0.0.0/24 is subnetted, 5 subnets
O E2 10.1.13.0 [110/20] via 10.1.34.3, 00:47:46, Ethernet0/0
O E2 10.1.12.0 [110/20] via 10.1.34.3, 00:47:46, Ethernet0/0
O E2 10.1.16.0 [110/20] via 10.1.34.3, 00:43:52, Ethernet0/0
O 10.1.23.0 [110/20] via 10.1.34.3, 00:47:47, Ethernet0/0
C 10.1.34.0 is directly connected, Ethernet0/0
R6#show ip route
1.0.0.0/32 is subnetted, 1 subnets
D 1.1.1.1 [90/409600] via 10.1.16.1, 00:00:07, Ethernet0/0
2.0.0.0/32 is subnetted, 1 subnets
D EX 2.2.2.2 [170/307456] via 10.1.16.1, 00:00:07, Ethernet0/0
3.0.0.0/32 is subnetted, 1 subnets
D EX 3.3.3.3 [170/307456] via 10.1.16.1, 00:00:07, Ethernet0/0
4.0.0.0/32 is subnetted, 1 subnets
D EX 4.4.4.4 [170/307456] via 10.1.16.1, 00:00:07, Ethernet0/0
6.0.0.0/32 is subnetted, 1 subnets
C 6.6.6.6 is directly connected, Loopback0
10.0.0.0/24 is subnetted, 5 subnets
D 10.1.13.0 [90/307200] via 10.1.16.1, 00:00:09, Ethernet0/0
D 10.1.12.0 [90/307200] via 10.1.16.1, 00:00:09, Ethernet0/0
C 10.1.16.0 is directly connected, Ethernet0/0
D EX 10.1.23.0 [170/307456] via 10.1.16.1, 00:00:10, Ethernet0/0
D EX 10.1.34.0 [170/307456] via 10.1.16.1, 00:00:10, Ethernet0/0
R4#traceroute 6.6.6.6
Type escape sequence to abort.
Tracing the route to 6.6.6.6
1 10.1.34.3 40 msec 28 msec 12 msec
2 10.1.13.1 52 msec 36 msec 44 msec
3 10.1.16.6 68 msec 48 msec 68 msec
R6#traceroute 4.4.4.4
Type escape sequence to abort.
Tracing the route to 4.4.4.4
1 10.1.16.1 20 msec 24 msec 12 msec
2 10.1.12.2 28 msec 20 msec 20 msec
3 10.1.23.3 36 msec 44 msec 12 msec
4 10.1.34.4 76 msec 76 msec 72 msec
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最佳答案
查看完整内容
做了重分布,外部路由的5类LSA会在全网泛洪,和R3做不做重分布没关系
双向重分布的知识要消化,把路由表中的路由好好看看,为会么路由表留下的是那种协议的
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