大家幫忙看看這道題答案

x9858627899

<interface>
% I9 j; x( O7 U  _& g- H  b  <loopback>
     <name>100</name>
     <enable>true</enable>
" p& m' ]* N* W  </loopback>

! [+ i: o6 s" }* R$ P- f2 H! W
1 N) k5 T% I; c' D% Y% ~<interface>
, o7 I8 ^) T- b' z3 d% R2 n
7 M0 m& V8 R, J- k
7 p  w6 _( F" T: k
* F# k7 ?& j1 fWhat is achieved by this code?
# e' g7 `+ A9 x5 \. K/ _" yA. It displays the loopback interface
B. It renames the loopback interface
C. It deletes the loopback interface
D. It unshuts the loopback interface
% u& F7 H- D! F9 E  h6 Q

; I6 n  T1 }' t: a% X, r9 b查不到啊...有些說D有些說A..沒有程式背景
, i9 y1 @: m) I0 [# m請各位幫忙看看唄

lincc

D:
enable就是noshut

: e% v5 L, b( r) g

thamky

D. It unshuts the loopback interface. Enable=true means unshut the port.

朱大帅爱皇马

D:
# G) b  ~8 b( @enable就是noshut:

jycert1

it should be D: enable the loopback 100

shangd

这不编程么？

tiang

D enable就是noshut